LeetCode Solutions
934. Shortest Bridge
Time: $O(n^2)$ Space: $O(n^2)$
class Solution {
public:
int shortestBridge(vector<vector<int>>& grid) {
markGridTwo(grid);
for (int color = 2;; ++color)
for (int i = 0; i < grid.size(); ++i)
for (int j = 0; j < grid[0].size(); ++j)
if (grid[i][j] == color)
if (expand(grid, i + 1, j, color) ||
expand(grid, i - 1, j, color) ||
expand(grid, i, j + 1, color) ||
expand(grid, i, j - 1, color))
return color - 2;
}
private:
// Mark one group to 2s by DFS
void markGridTwo(vector<vector<int>>& grid) {
for (int i = 0; i < grid.size(); ++i)
for (int j = 0; j < grid[0].size(); ++j)
if (grid[i][j] == 1) {
markGridTwo(grid, i, j);
return;
}
}
void markGridTwo(vector<vector<int>>& grid, int i, int j) {
if (i < 0 || i == grid.size() || j < 0 || j == grid[0].size())
return;
if (grid[i][j] != 1)
return;
grid[i][j] = 2;
markGridTwo(grid, i + 1, j);
markGridTwo(grid, i - 1, j);
markGridTwo(grid, i, j + 1);
markGridTwo(grid, i, j - 1);
}
// Expand from colors' group to 1s' group
bool expand(vector<vector<int>>& grid, int i, int j, int color) {
if (i < 0 || i == grid.size() || j < 0 || j == grid[0].size())
return false;
if (grid[i][j] == 0)
grid[i][j] = color + 1;
return grid[i][j] == 1; // We touch the 1s' group!
}
};
class Solution {
public int shortestBridge(int[][] grid) {
markGridTwo(grid);
for (int color = 2;; ++color)
for (int i = 0; i < grid.length; ++i)
for (int j = 0; j < grid[0].length; ++j)
if (grid[i][j] == color)
if (expand(grid, i + 1, j, color) || expand(grid, i - 1, j, color) ||
expand(grid, i, j + 1, color) || expand(grid, i, j - 1, color))
return color - 2;
}
// Mark one group to 2s by DFS
private void markGridTwo(int[][] grid) {
for (int i = 0; i < grid.length; ++i)
for (int j = 0; j < grid[0].length; ++j)
if (grid[i][j] == 1) {
markGridTwo(grid, i, j);
return;
}
}
private void markGridTwo(int[][] grid, int i, int j) {
if (i < 0 || i == grid.length || j < 0 || j == grid[0].length)
return;
if (grid[i][j] != 1)
return;
grid[i][j] = 2;
markGridTwo(grid, i + 1, j);
markGridTwo(grid, i - 1, j);
markGridTwo(grid, i, j + 1);
markGridTwo(grid, i, j - 1);
}
// Expand from colors' group to 1s' group
private boolean expand(int[][] grid, int i, int j, int color) {
if (i < 0 || i == grid.length || j < 0 || j == grid[0].length)
return false;
if (grid[i][j] == 0)
grid[i][j] = color + 1;
return grid[i][j] == 1; // We touch the 1s' group!
}
}
class Solution {
public:
int shortestBridge(vector<vector<int>>& grid) {
const int n = grid.size();
const vector<int> dirs{0, 1, 0, -1, 0};
int ans = 0;
queue<pair<int, int>> q;
markGridTwo(grid, q);
// Expand by BFS
while (!q.empty()) {
for (int sz = q.size(); sz > 0; --sz) {
const auto [i, j] = q.front();
q.pop();
for (int k = 0; k < 4; ++k) {
const int x = i + dirs[k];
const int y = j + dirs[k + 1];
if (x < 0 || x == n || y < 0 || y == n)
continue;
if (grid[x][y] == 2)
continue;
if (grid[x][y] == 1)
return ans;
grid[x][y] = 2;
q.emplace(x, y);
}
}
++ans;
}
throw;
}
private:
// Mark one group to 2s by DFS
void markGridTwo(vector<vector<int>>& grid, queue<pair<int, int>>& q) {
for (int i = 0; i < grid.size(); ++i)
for (int j = 0; j < grid[0].size(); ++j)
if (grid[i][j] == 1) {
markGridTwo(grid, i, j, q);
return;
}
}
// Mark one group to 2s by DFS and push them to the q
void markGridTwo(vector<vector<int>>& grid, int i, int j,
queue<pair<int, int>>& q) {
if (i < 0 || i == grid.size() || j < 0 || j == grid[0].size())
return;
if (grid[i][j] != 1)
return;
grid[i][j] = 2;
q.emplace(i, j);
markGridTwo(grid, i + 1, j, q);
markGridTwo(grid, i - 1, j, q);
markGridTwo(grid, i, j + 1, q);
markGridTwo(grid, i, j - 1, q);
}
};