LeetCode Solutions
505. The Maze II
Time: $O(mn \cdot \max(m, n))$ Space: $O(\max(m, n))$
class Solution {
public:
int shortestDistance(vector<vector<int>>& maze, vector<int>& start,
vector<int>& destination) {
const int m = maze.size();
const int n = maze[0].size();
const vector<int> dirs{0, 1, 0, -1, 0};
queue<pair<int, int>> q{{{start[0], start[1]}}};
vector<vector<int>> dist(m, vector<int>(n, INT_MAX));
dist[start[0]][start[1]] = 0;
while (!q.empty()) {
const auto [i, j] = q.front();
q.pop();
for (int k = 0; k < 4; ++k) {
int x = i;
int y = j;
int steps = dist[i][j];
while (isValid(maze, x + dirs[k], y + dirs[k + 1])) {
x += dirs[k];
y += dirs[k + 1];
++steps;
}
if (steps < dist[x][y]) {
dist[x][y] = steps;
if (x == destination[0] && y == destination[1])
continue;
q.emplace(x, y);
}
}
}
return dist[destination[0]][destination[1]] == INT_MAX
? -1
: dist[destination[0]][destination[1]];
}
private:
bool isValid(const vector<vector<int>>& maze, int x, int y) {
return x >= 0 && x < maze.size() && y >= 0 && y < maze[0].size() &&
maze[x][y] == 0;
}
};
class Solution {
public int shortestDistance(int[][] maze, int[] start, int[] destination) {
final int m = maze.length;
final int n = maze[0].length;
final int[] dirs = {0, 1, 0, -1, 0};
Queue<int[]> q = new ArrayDeque<>(Arrays.asList(new int[] {start[0], start[1]}));
int[][] dist = new int[maze.length][maze[0].length];
Arrays.stream(dist).forEach(row -> Arrays.fill(row, Integer.MAX_VALUE));
dist[start[0]][start[1]] = 0;
while (!q.isEmpty()) {
final int i = q.peek()[0];
final int j = q.poll()[1];
for (int k = 0; k < 4; ++k) {
int x = i;
int y = j;
int steps = dist[i][j];
while (isValid(maze, x + dirs[k], y + dirs[k + 1])) {
x += dirs[k];
y += dirs[k + 1];
++steps;
}
if (steps < dist[x][y]) {
dist[x][y] = steps;
q.offer(new int[] {x, y});
}
}
}
return dist[destination[0]][destination[1]] == Integer.MAX_VALUE
? -1
: dist[destination[0]][destination[1]];
}
private boolean isValid(int[][] maze, int x, int y) {
return x >= 0 && x < maze.length && y >= 0 && y < maze[0].length && maze[x][y] == 0;
}
}