LeetCode Solutions

48. Rotate Image

Time: $O(n^2)$

Space: $O(1)$

			

class Solution {
 public:
  void rotate(vector<vector<int>>& matrix) {
    reverse(begin(matrix), end(matrix));
    for (int i = 0; i < matrix.size(); ++i)
      for (int j = i + 1; j < matrix.size(); ++j)
        swap(matrix[i][j], matrix[j][i]);
  }
};
			

class Solution {
  public void rotate(int[][] matrix) {
    for (int i = 0, j = matrix.length - 1; i < j; ++i, --j) {
      int[] temp = matrix[i];
      matrix[i] = matrix[j];
      matrix[j] = temp;
    }

    for (int i = 0; i < matrix.length; ++i)
      for (int j = i + 1; j < matrix.length; ++j) {
        final int temp = matrix[i][j];
        matrix[i][j] = matrix[j][i];
        matrix[j][i] = temp;
      }
  }
}
			

class Solution:
  def rotate(self, matrix: List[List[int]]) -> None:
    matrix.reverse()

    for i in range(len(matrix)):
      for j in range(i + 1, len(matrix)):
        matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]