LeetCode Solutions

			

enum class State { kInit, kVisiting, kVisited };

class Solution {
 public:
  vector<int> findOrder(int numCourses, vector<vector<int>>& prerequisites) {
    vector<int> ans;
    vector<vector<int>> graph(numCourses);
    vector<State> state(numCourses);

    for (const auto& p : prerequisites)
      graph[p[1]].push_back(p[0]);

    for (int i = 0; i < numCourses; ++i)
      if (hasCycle(graph, i, state, ans))
        return {};

    reverse(begin(ans), end(ans));
    return ans;
  }

 private:
  bool hasCycle(const vector<vector<int>>& graph, int u, vector<State>& state,
                vector<int>& ans) {
    if (state[u] == State::kVisiting)
      return true;
    if (state[u] == State::kVisited)
      return false;

    state[u] = State::kVisiting;
    for (const int v : graph[u])
      if (hasCycle(graph, v, state, ans))
        return true;
    state[u] = State::kVisited;
    ans.push_back(u);

    return false;
  }
};

			

enum State { kInit, kVisiting, kVisited }

class Solution {
  public int[] findOrder(int numCourses, int[][] prerequisites) {
    Deque<Integer> ans = new ArrayDeque<>();
    List<Integer>[] graph = new List[numCourses];
    State[] state = new State[numCourses];

    for (int i = 0; i < numCourses; ++i)
      graph[i] = new ArrayList<>();

    for (int[] p : prerequisites)
      graph[p[1]].add(p[0]);

    for (int i = 0; i < numCourses; ++i)
      if (hasCycle(graph, i, state, ans))
        return new int[] {};

    return ans.stream().mapToInt(Integer::intValue).toArray();
  }

  private boolean hasCycle(List<Integer>[] graph, int u, State[] state, Deque<Integer> ans) {
    if (state[u] == State.kVisiting)
      return true;
    if (state[u] == State.kVisited)
      return false;

    state[u] = State.kVisiting;
    for (final int v : graph[u])
      if (hasCycle(graph, v, state, ans))
        return true;
    state[u] = State.kVisited;
    ans.addFirst(u);

    return false;
  }
}

			

from enum import Enum


class State(Enum):
  kInit = 0
  kVisiting = 1
  kVisited = 2


class Solution:
  def findOrder(self, numCourses: int, prerequisites: List[List[int]]) -> List[int]:
    ans = []
    graph = [[] for _ in range(numCourses)]
    state = [State.kInit] * numCourses

    for v, u in prerequisites:
      graph[u].append(v)

    def hasCycle(u: int) -> bool:
      if state[u] == State.kVisiting:
        return True
      if state[u] == State.kVisited:
        return False

      state[u] = State.kVisiting
      if any(hasCycle(v) for v in graph[u]):
        return True
      state[u] = State.kVisited
      ans.append(u)

      return False

    if any(hasCycle(i) for i in range(numCourses)):
      return []

    return ans[::-1]