LeetCode Solutions
407. Trapping Rain Water II
Time: $O(mn\log mn)$ Space: $O(mn)$
struct T {
int i;
int j;
int h; // heightMap[i][j] or the height after filling water
T(int i, int j, int h) : i(i), j(j), h(h) {}
};
class Solution {
public:
int trapRainWater(vector<vector<int>>& heightMap) {
const int m = heightMap.size();
const int n = heightMap[0].size();
const vector<int> dirs{0, 1, 0, -1, 0};
int ans = 0;
auto compare = [](const T& a, const T& b) { return a.h > b.h; };
priority_queue<T, vector<T>, decltype(compare)> minHeap(compare);
vector<vector<bool>> seen(m, vector<bool>(n));
for (int i = 0; i < m; ++i) {
minHeap.emplace(i, 0, heightMap[i][0]);
minHeap.emplace(i, n - 1, heightMap[i][n - 1]);
seen[i][0] = true;
seen[i][n - 1] = true;
}
for (int j = 1; j < n - 1; ++j) {
minHeap.emplace(0, j, heightMap[0][j]);
minHeap.emplace(m - 1, j, heightMap[m - 1][j]);
seen[0][j] = true;
seen[m - 1][j] = true;
}
while (!minHeap.empty()) {
const auto [i, j, h] = minHeap.top();
minHeap.pop();
for (int k = 0; k < 4; ++k) {
const int x = i + dirs[k];
const int y = j + dirs[k + 1];
if (x < 0 || x == m || y < 0 || y == n)
continue;
if (seen[x][y])
continue;
if (heightMap[x][y] < h) {
ans += h - heightMap[x][y];
minHeap.emplace(x, y, h); // Fill the water on grid[x][y]
} else {
minHeap.emplace(x, y, heightMap[x][y]);
}
seen[x][y] = true;
}
}
return ans;
}
};
class T {
public int i;
public int j;
public int h; // heightMap[i][j] or the height after filling water
public T(int i, int j, int h) {
this.i = i;
this.j = j;
this.h = h;
}
}
class Solution {
public int trapRainWater(int[][] heightMap) {
final int m = heightMap.length;
final int n = heightMap[0].length;
final int[] dirs = {0, 1, 0, -1, 0};
int ans = 0;
Queue<T> minHeap = new PriorityQueue<>((a, b) -> a.h - b.h);
boolean[][] seen = new boolean[m][n];
for (int i = 0; i < m; ++i) {
minHeap.offer(new T(i, 0, heightMap[i][0]));
minHeap.offer(new T(i, n - 1, heightMap[i][n - 1]));
seen[i][0] = true;
seen[i][n - 1] = true;
}
for (int j = 1; j < n - 1; ++j) {
minHeap.offer(new T(0, j, heightMap[0][j]));
minHeap.offer(new T(m - 1, j, heightMap[m - 1][j]));
seen[0][j] = true;
seen[m - 1][j] = true;
}
while (!minHeap.isEmpty()) {
final int i = minHeap.peek().i;
final int j = minHeap.peek().j;
final int h = minHeap.poll().h;
for (int k = 0; k < 4; ++k) {
final int x = i + dirs[k];
final int y = j + dirs[k + 1];
if (x < 0 || x == m || y < 0 || y == n)
continue;
if (seen[x][y])
continue;
if (heightMap[x][y] < h) {
ans += h - heightMap[x][y];
minHeap.offer(new T(x, y, h)); // Fill the water on grid[x][y]
} else {
minHeap.offer(new T(x, y, heightMap[x][y]));
}
seen[x][y] = true;
}
}
return ans;
}
}