LeetCode Solutions
1034. Coloring A Border
Time: $O(mn)$ Space: $O(mn)$
class Solution {
public:
vector<vector<int>> colorBorder(vector<vector<int>>& grid, int r0, int c0,
int color) {
dfs(grid, r0, c0, grid[r0][c0]);
for (int i = 0; i < grid.size(); ++i)
for (int j = 0; j < grid[0].size(); ++j)
if (grid[i][j] < 0)
grid[i][j] = color;
return grid;
}
private:
void dfs(vector<vector<int>>& grid, int i, int j, int startColor) {
if (i < 0 || i == grid.size() || j < 0 || j == grid[0].size())
return;
if (grid[i][j] != startColor)
return;
grid[i][j] = -startColor; // Mark
dfs(grid, i + 1, j, startColor);
dfs(grid, i - 1, j, startColor);
dfs(grid, i, j + 1, startColor);
dfs(grid, i, j - 1, startColor);
// If this cell already on the boarder, it must be painted later
if (i == 0 || i == grid.size() - 1 || j == 0 || j == grid[0].size() - 1)
return;
if (abs(grid[i + 1][j]) == startColor &&
abs(grid[i - 1][j]) == startColor &&
abs(grid[i][j + 1]) == startColor &&
abs(grid[i][j - 1]) == startColor)
grid[i][j] = startColor;
}
};
class Solution {
public int[][] colorBorder(int[][] grid, int r0, int c0, int color) {
dfs(grid, r0, c0, grid[r0][c0]);
for (int i = 0; i < grid.length; ++i)
for (int j = 0; j < grid[0].length; ++j)
if (grid[i][j] < 0)
grid[i][j] = color;
return grid;
}
private void dfs(int[][] grid, int i, int j, int startColor) {
if (i < 0 || i == grid.length || j < 0 || j == grid[0].length)
return;
if (grid[i][j] != startColor)
return;
grid[i][j] = -startColor; // Mark
dfs(grid, i + 1, j, startColor);
dfs(grid, i - 1, j, startColor);
dfs(grid, i, j + 1, startColor);
dfs(grid, i, j - 1, startColor);
// If this cell already on the boarder, it must be painted later
if (i == 0 || i == grid.length - 1 || j == 0 || j == grid[0].length - 1)
return;
if (Math.abs(grid[i + 1][j]) == startColor &&
Math.abs(grid[i - 1][j]) == startColor &&
Math.abs(grid[i][j + 1]) == startColor &&
Math.abs(grid[i][j - 1]) == startColor)
grid[i][j] = startColor;
}
}
class Solution:
def colorBorder(self, grid: List[List[int]], r0: int, c0: int, color: int) -> List[List[int]]:
def dfs(i: int, j: int, originalColor: int) -> None:
if not 0 <= i < len(grid) or not 0 <= j < len(grid[0]) or grid[i][j] != originalColor:
return
grid[i][j] = -originalColor
dfs(i + 1, j, originalColor)
dfs(i - 1, j, originalColor)
dfs(i, j + 1, originalColor)
dfs(i, j - 1, originalColor)
if 0 < i < len(grid) - 1 and 0 < j < len(grid[0]) - 1 and \
abs(grid[i + 1][j]) == originalColor and \
abs(grid[i - 1][j]) == originalColor and \
abs(grid[i][j + 1]) == originalColor and \
abs(grid[i][j - 1]) == originalColor:
grid[i][j] = originalColor
dfs(r0, c0, grid[r0][c0])
for i in range(len(grid)):
for j in range(len(grid[0])):
if grid[i][j] < 0:
grid[i][j] = color
return grid