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LeetCode Solutions

623. Add One Row to Tree

Time: $O(n)$

Space: $O(n)$

			


class Solution {
 public:
  TreeNode* addOneRow(TreeNode* root, int v, int d) {
    if (d == 1) {
      TreeNode* newRoot = new TreeNode(v);
      newRoot->left = root;
      return newRoot;
    }

    int depth = 0;
    queue<TreeNode*> q{{root}};

    while (!q.empty()) {
      ++depth;
      for (int sz = q.size(); sz > 0; --sz) {
        TreeNode* node = q.front();
        q.pop();
        if (node->left)
          q.push(node->left);
        if (node->right)
          q.push(node->right);
        if (depth == d - 1) {
          TreeNode* cachedLeft = node->left;
          TreeNode* cachedRight = node->right;
          node->left = new TreeNode(v);
          node->right = new TreeNode(v);
          node->left->left = cachedLeft;
          node->right->right = cachedRight;
        }
      }
      if (depth == d - 1)
        break;
    }

    return root;
  }
};




			


class Solution {
  public TreeNode addOneRow(TreeNode root, int v, int d) {
    if (d == 1) {
      TreeNode newRoot = new TreeNode(v);
      newRoot.left = root;
      return newRoot;
    }

    int depth = 0;
    Queue<TreeNode> q = new ArrayDeque<>(Arrays.asList(root));

    while (!q.isEmpty()) {
      ++depth;
      for (int sz = q.size(); sz > 0; --sz) {
        TreeNode node = q.poll();
        if (node.left != null)
          q.offer(node.left);
        if (node.right != null)
          q.offer(node.right);
        if (depth == d - 1) {
          TreeNode cachedLeft = node.left;
          TreeNode cachedRight = node.right;
          node.left = new TreeNode(v);
          node.right = new TreeNode(v);
          node.left.left = cachedLeft;
          node.right.right = cachedRight;
        }
      }
      if (depth == d - 1)
        break;
    }

    return root;
  }
}