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LeetCode Solutions

469. Convex Polygon

Time: $O(n)$

Space: $O(1)$

			


class Solution {
 public:
  bool isConvex(vector<vector<int>>& points) {
    auto getCross = [](const vector<int>& p, const vector<int>& q,
                       const vector<int>& r) -> int {
      return (q[0] - p[0]) * (r[1] - p[1]) - (q[1] - p[1]) * (r[0] - p[0]);
    };

    const int n = points.size();
    long sign = 0;

    for (int i = 0; i < points.size(); ++i) {
      const int cross =
          getCross(points[i], points[(i + 1) % n], points[(i + 2) % n]);
      if (cross == 0)  // P, q, r are collinear
        continue;
      if (sign == 0)  // Find first cross that's not 0
        sign = cross;
      else if (cross * sign < 0)
        return false;
    }

    return true;
  }
};




			


class Solution {
  public boolean isConvex(List<List<Integer>> points) {
    final int n = points.size();
    long sign = 0;

    for (int i = 0; i < n; ++i) {
      final int cross = getCross(points.get(i), points.get((i + 1) % n), points.get((i + 2) % n));
      if (cross == 0) // P, q, r are collinear
        continue;
      if (sign == 0) // Find first cross that's not 0
        sign = cross;
      else if (cross * sign < 0)
        return false;
    }

    return true;
  }

  private int getCross(List<Integer> p, List<Integer> q, List<Integer> r) {
    return (q.get(0) - p.get(0)) * (r.get(1) - p.get(1)) -
        (q.get(1) - p.get(1)) * (r.get(0) - p.get(0));
  }
}




			


class Solution:
  def isConvex(self, points: List[List[int]]) -> bool:
    # Pq x qr
    def getCross(p: List[int], q: List[int], r: List[int]):
      return (q[0] - p[0]) * (r[1] - p[1]) - (q[1] - p[1]) * (r[0] - p[0])

    sign = 0
    for i in range(len(points)):
      cross = getCross(points[i - 2], points[i - 1], points[i])
      if cross == 0:  # P, q, r are collinear
        continue
      if sign == 0:  # Find first cross that's not 0
        sign = cross
      elif cross * sign < 0:
        return False

    return True