Home
Algorithms Data Structures Interview Experiences
Amazon Google Facebook Microsoft Apple Netflix
Play 2048 How to

LeetCode Solutions

702. Search in a Sorted Array of Unknown Size

Time: $O(\log 10^4)$

Space: $O(1)$

			


/**
 * // This is the ArrayReader's API interface.
 * // You should not implement it, or speculate about its implementation
 * class ArrayReader {
 *  public:
 *   int get(int index);
 * };
 */

class Solution {
 public:
  int search(const ArrayReader& reader, int target) {
    int l = 0;
    int r = 1e4;

    while (l < r) {
      const int m = (l + r) / 2;
      if (reader.get(m) < target)
        l = m + 1;
      else
        r = m;
    }

    return reader.get(l) == target ? l : -1;
  }
};




			


/**
 * // This is ArrayReader's API interface.
 * // You should not implement it, or speculate about its implementation
 * interface ArrayReader {
 *   public int get(int index) {}
 * }
 */

class Solution {
  public int search(ArrayReader reader, int target) {
    int l = 0;
    int r = (int) 1e4;

    while (l < r) {
      final int m = (l + r) / 2;
      if (reader.get(m) < target)
        l = m + 1;
      else
        r = m;
    }

    return reader.get(l) == target ? l : -1;
  }
}




			


# """
# This is ArrayReader's API interface.
# You should not implement it, or speculate about its implementation
# """
# Class ArrayReader:
#   def get(self, index: int) -> int:

class Solution:
  def search(self, reader: 'ArrayReader', target: int) -> int:
    l = 0
    r = 10**4

    while l < r:
      m = (l + r) // 2
      if reader.get(m) < target:
        l = m + 1
      else:
        r = m

    return l if reader.get(l) == target else -1