LeetCode Solutions
383. Ransom Note
Time: $O(|\texttt{ransomNote}| + |\texttt{magazine}|)$ Space: $O(128) = O(1)$
class Solution {
public:
bool canConstruct(string ransomNote, string magazine) {
vector<int> count(128);
for (const char c : magazine)
++count[c];
for (const char c : ransomNote)
if (--count[c] < 0)
return false;
return true;
}
};
class Solution {
public boolean canConstruct(String ransomNote, String magazine) {
int[] count = new int[128];
for (final char c : magazine.toCharArray())
++count[c];
for (final char c : ransomNote.toCharArray())
if (--count[c] < 0)
return false;
return true;
}
}
class Solution:
def canConstruct(self, ransomNote: str, magazine: str) -> bool:
count1 = Counter(ransomNote)
count2 = Counter(magazine)
return all(count1[c] <= count2[c] for c in string.ascii_lowercase)