LeetCode Solutions
452. Minimum Number of Arrows to Burst Balloons
Time: $O(n\log n)$ Space: $O(1)$
class Solution {
public:
int findMinArrowShots(vector<vector<int>>& points) {
sort(begin(points), end(points),
[](const auto& a, const auto& b) { return a[1] < b[1]; });
int ans = 1;
int arrowX = points[0][1];
for (int i = 1; i < points.size(); ++i)
if (points[i][0] > arrowX) {
arrowX = points[i][1];
++ans;
}
return ans;
}
};
class Solution {
public int findMinArrowShots(int[][] points) {
Arrays.sort(points, (a, b) -> a[1] - b[1]);
int ans = 1;
int arrowX = points[0][1];
for (int i = 1; i < points.length; ++i)
if (points[i][0] > arrowX) {
arrowX = points[i][1];
++ans;
}
return ans;
}
}
class Solution:
def findMinArrowShots(self, points: List[List[int]]) -> int:
ans = 0
arrowX = -math.inf
for point in sorted(points, key=lambda x: x[1]):
if point[0] > arrowX:
ans += 1
arrowX = point[1]
return ans